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Proof step 17 from proof remove-refsize0-refsize-cons (previous step)

st[m] = mkblock(x, lax, 0), inv(st), @(m, m0, m1) ∈ st, @(m, m0, m1) ∈ as, m ∈ st, as ⊆ dom nodes(st), ∀ adr. adr ∈ as | m → adr.size = 0 ⊦ # as = 0, as = ∅, dom nodes(st) ⊆ dom nodes(remove-refsize0(st))

User applied rule all left

And obtained the following new goals

Proof step 18:
st[m] = mkblock(x, lax, 0), inv(st), m ∈ st, @(m, m0, m1) ∈ as, @(m, m0, m1) ∈ st, as ⊆ dom nodes(st), @(m, m0, m1) ∈ as | m → @(m, m0, m1).size = 0 ⊦ # as = 0, as = ∅, dom nodes(st) ⊆ dom nodes(remove-refsize0(st))

Rule argument

pos: left 7 terms: @(m, m0, m1) abort: F discard: T computed: T

Additional information

Used terms: @(m, m0, m1)