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Proof step 22 from proof remove-refsize0-refsize-cons (previous step)

st[m] = mkblock(x, lax, 0), @(m, m0, 0) ∈ as, m ∈ st, @(m, m0, 0) ∈ st, as ⊆ dom nodes(st), m ∈ st → inv(st[m]) ⊦ # as = 0, as = ∅, dom nodes(st) ⊆ dom nodes(remove-refsize0(st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
st[m] = mkblock(x, lax, 0), inv(mkblock(x, lax, 0)), @(m, m0, 0) ∈ st, m ∈ st, @(m, m0, 0) ∈ as, as ⊆ dom nodes(st) ⊦ # as = 0, as = ∅, dom nodes(st) ⊆ dom nodes(remove-refsize0(st))

Proof step 22 from proof remove-refsize0-refsize-cons (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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