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Proof step 6 from proof remove-refsize0-refsize-cons (previous step)

inv(st), adr ∈ as, adr ∈ st, as ⊆ dom nodes(st), ∀ n. n ∈ st → st[n].ref-size = (as | n).size ⊦ # as = 0, as = ∅, adr ∈ remove-refsize0(st), dom nodes(st) ⊆ dom nodes(remove-refsize0(st))

User applied rule constructor cut

And obtained the following new goals

Proof step 7:
adr = @(m, m0, m1), inv(st), adr ∈ st, adr ∈ as, as ⊆ dom nodes(st), ∀ n. n ∈ st → st[n].ref-size = (as | n).size ⊦ # as = 0, as = ∅, adr ∈ remove-refsize0(st), dom nodes(st) ⊆ dom nodes(remove-refsize0(st))

Rule argument

var: adr

Additional information

Used simplifier rules: address freely generated by @;;