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Proof step 26 from proof remove-refsize0-subset-refed (previous step)

st[m] = mkblock(x, lax, m2), m ∈ st, @(m, m0, m1) ∈ st, @(m, m0, m1) ∈ as, @(m, m0, m1) ∈ remove-refsize0(st), as ⊆ dom nodes(st), ∀ n. n ∈ st → st[n].ref-size = (as | n).size, ∀ adr. adr ∈ as → adr.size ≠ 0 ⊦ # as = 0, st[@(m, m0, m1)] = x[pos(@(m0, m1), lax)], as = ∅, m2 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: ablock-store-inv name: at seq: ⊦ adr ∈ st → st[adr] = st[adr.lnum].list [pos(@(adr.pos, adr.size), st[adr.lnum].ladrlist) ] subst: [adr, st] → [@(m, m0, m1), st] flags: <all paths>

Additional information

Used simplifier rules: ⊦ @(m, m0, m1).lnum = m; (s)% ⊦ @(m, m0, m1).pos = m0; (s)% ⊦ @(m, m0, m1).size = m1; (s)% ⊦ mkblock(x, lax, m).list = x; (s)% ⊦ mkblock(x, lax, m).ladrlist = lax; (s) Used terms: @(m, m0, m1), st