[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 36 from proof remove-refsize0-subset-refed (previous step)

st[m] = mkblock(x0, lax0, 0), (∅)[m] = mkblock(x, lax, m2), @(m, m0, m1) ∈ as, @(m, m0, m1) ∈ st, m ∈ st, as ⊆ dom nodes(st), ∀ n. n ∈ st → st[n].ref-size = (as | n).size ⊦ # as = 0, as = ∅, m1 = 0

User applied rule all left

And obtained the following new goals

Proof step 37:
(∅)[m] = mkblock(x, lax, m2), st[m] = mkblock(x0, lax0, 0), m ∈ st, @(m, m0, m1) ∈ st, @(m, m0, m1) ∈ as, as ⊆ dom nodes(st), m ∈ st → st[m].ref-size = (as | m).size ⊦ # as = 0, as = ∅, m1 = 0

Rule argument

pos: left 7 terms: m abort: F discard: T computed: T

Additional information

Used terms: m