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Proof step 38 from proof remove-refsize0-subset-refed (previous step)

0 = (as | m).size, (∅)[m] = mkblock(x, lax, m2), st[m] = mkblock(x0, lax0, 0), m ∈ st, @(m, m0, m1) ∈ st, @(m, m0, m1) ∈ as, as ⊆ dom nodes(st) ⊦ # as = 0, as = ∅, m1 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 39:
⊦ 0 = as.size ↔ (∀ adr. adr ∈ as → adr.size = 0)
Proof step 40:
st[m] = mkblock(x0, lax0, 0), (∅)[m] = mkblock(x, lax, m2), @(m, m0, m1) ∈ as, @(m, m0, m1) ∈ st, m ∈ st, as ⊆ dom nodes(st), ∀ adr. adr ∈ as | m → adr.size = 0 ⊦ # as = 0, as = ∅, m1 = 0

Rule argument

spec: <toplevel> name: size-eq-0 seq: ⊦ 0 = as.size ↔ (∀ adr. adr ∈ as → adr.size = 0) subst: [as] → [as | m] flags: <all paths>

Additional information

Used terms: as | m