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Proof step 3 from proof restrict-add-other (previous step)

⊦ m = m0, (as ++ @(m0, m1, m2)) | m = as | m

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ as = as0 ↔ (∀ adr. adr ∈ as ↔ adr ∈ as0)
Proof step 5:
⊦ m = m0, ∀ adr. adr ∈ (as ++ @(m0, m1, m2)) | m ↔ adr ∈ as | m

Rule argument

spec: set-basic, inst: address-store name: Extension seq: ⊦ as = as0 ↔ (∀ adr. adr ∈ as ↔ adr ∈ as0) subst: [as0, as] → [as | m, (as ++ @(m0, m1, m2)) | m] flags: <all paths>

Additional information

Used terms: as | m, (as ++ @(m0, m1, m2)) | m