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Proof step 4 from proof restrict-del (previous step)

⊦ adr ∈ (as -- @(m, m0, m1)) | m ↔ adr ≠ @(m, m0, m1) ∧ adr ∈ as | m

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: restrict-leb seq: ⊦ adr ∈ as | n ↔ adr.lnum = n ∧ adr ∈ as subst: [n, as, adr] → [m, as -- @(m, m0, m1), adr] flags: <all paths>

Additional information

Used simplifier rules: restrict-leb: ⊦ adr ∈ as | n ↔ adr.lnum = n ∧ adr ∈ as;% ⊦ adr ∈ as -- adr0 ↔ adr ≠ adr0 ∧ adr ∈ as; (s) Used terms: m, as -- @(m, m0, m1), adr