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Proof step 2 from proof restrict-empty (previous step)

⊦ #(∅ | n) = 0, ∅ | n = ∅

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ as = as0 ↔ (∀ adr. adr ∈ as ↔ adr ∈ as0)

Rule argument

spec: set-basic, inst: address-store name: Extension seq: ⊦ as = as0 ↔ (∀ adr. adr ∈ as ↔ adr ∈ as0) subst: [as0, as] → [∅, ∅ | n] flags: <all paths>

Additional information

Used simplifier rules: restrict-leb: ⊦ adr ∈ as | n ↔ adr.lnum = n ∧ adr ∈ as;% ⊦ ¬ adr ∈ ∅; (s) Used terms: ∅, ∅ | n