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Proof step 1 from proof restrict-in (conclusion)

⊦ @(m, m0, m1) ∈ as | m ↔ @(m, m0, m1) ∈ as

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: restrict-leb: ⊦ adr ∈ as | n ↔ adr.lnum = n ∧ adr ∈ as;% ⊦ @(m, m0, m1).lnum = m; (s)