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Proof step 11 from proof restrict-union-inter-empty-left (previous step)

⊦ m = n ∧ @(n, m0, m1) ∈ as0 ∧ @(n, m0, m1) ∈ (as1 \ (as1 | n)) ∪ as2 ↔ @(m, m0, m1) ∈ (as0 | n) ∩ as2

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: set-union, inst: address-store name: Union seq: ⊦ adr ∈ as ∪ as0 ↔ adr ∈ as ∨ adr ∈ as0 subst: [as0, as, adr] → [as2, as1 \ (as1 | n), @(n, m0, m1)] flags: <all paths>

Additional information

Used terms: as2, as1 \ (as1 | n), @(n, m0, m1)