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Proof step 8 from proof restrict-union-inter-empty-left (
previous step
)
⊦ (adr.lnum = n ∧ adr ∈ as0) ∧ adr ∈ (as1 \ (as1 | n)) ∪ as2 ↔ adr ∈ (as0 | n) ∩ as2
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 9
:
⊦ adr.lnum = n ∧ adr ∈ as0 ∧ adr ∈ (as1 \ (as1 | adr.lnum)) ∪ as2 ↔ adr ∈ (as0 | n) ∩ as2
Rule argument
Additional information