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Proof step 2 from proof size-eq-0-alloc (previous step)

as ⊆ dom nodes(st) ⊦ (as | n).size = 0, n ∈ st

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: size-eq-0 seq: ⊦ 0 = as.size ↔ (∀ adr. adr ∈ as → adr.size = 0) subst: [as] → [as | n] flags: <all paths>

Additional information

Used simplifier rules: subseteq-dom-nodes-alloc-restrict-empty: ⊦ as ⊆ dom nodes(st) ∧ ¬ n ∈ st → as | n = ∅;% ⊦ ¬ adr ∈ ∅; (s) Used terms: as | n