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Proof step 4 from proof size-rem (
previous step
)
adr = @(m, m0, m1), adr ∈ as ⊦ # as = 0, (as -- adr).size = as.size - m1, as = ∅
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 5
:
@(m, m0, m1) ∈ as ⊦ # as = 0, (as -- @(m, m0, m1)).size = as.size - m1, as = ∅
Rule argument
Additional information