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Proof step 2 from proof subseteq-dom-nodes-alloc-restrict-empty (previous step)

as ⊆ dom nodes(st) ⊦ as | n = ∅, n ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
as ⊆ dom nodes(st) ⊦ #(as | n) = 0, as | n = ∅, n ∈ st

Rule argument

Additional information

Used simplifier rules: size-zero: ⊦ # as ≠ 0 → as ≠ ∅; (forward) from specification set-basic[address-store]%size-zero-01: ⊦ as ≠ ∅ → # as ≠ 0; (forward) from specification set-basic[address-store]