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Proof step 12 from proof abs-failed-abs-nodes-h (previous step)

x = nd + x0, abs-failed(buf) ⊦ abs-nodes(buf, n, x, lax, weak) ↔ lax = [] ∧ x = [] ∧ weak

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
abs-failed(buf), abs-nodes(buf, n, nd ' + x0, lax, weak) ⊦

Rule argument

Additional information

Used simplifier rules: a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ a ' + x ≠ []; (s)% ⊦ a + x = a ' + x; (s)