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Proof step 16 from proof abs-failed-abs-nodes-h (previous step)

abs-failed(buf1 + buf0), abs-padding(buf1) ∧ abs-nodes(buf0, n + # buf1, nd ' + x0, lax, weak) ∨ lax ≠ [] ∧ lax.head.off = n ∧ lax.head.size = # buf1 ∧ abs-node(buf1, nd) ∧ abs-nodes(buf0, lax.head.off + # buf1, x0, lax.tail, weak) ⊦

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 17:
lax.head = @(m, m0), abs-failed(buf1 + buf0), abs-padding(buf1) ∧ abs-nodes(buf0, n + # buf1, nd ' + x0, lax, weak) ∨ lax ≠ [] ∧ m = n ∧ m0 = # buf1 ∧ abs-node(buf1, nd) ∧ abs-nodes(buf0, m + # buf1, x0, lax.tail, weak) ⊦

Rule argument

spec: laddress name: elim seq: ⊦ m = ladr.off ∧ m0 = ladr.size ↔ ladr = @(m, m0) subst: [ladr, m, m0] → [lax.head, m, m0]

Additional information

Used simplifier rules: ⊦ m = ladr.off ∧ m0 = ladr.size ↔ ladr = @(m, m0); (elim) Used terms: lax.head, m, m0