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Proof step 5 from proof abs-failed-abs-nodes-h (previous step)

abs-failed(buf) ⊦ abs-nodes(buf, n, [], lax, weak) ↔ lax = [] ∧ weak

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ abs-nodes(buf, m, [], lax, weak) ↔ # buf = 0 ∧ lax = [] ∨ (∃ buf0, buf1. buf = buf0 + buf1 ∧ abs-padding(buf0) ∧ abs-nodes(buf1, m + # buf0, [], lax, weak)) ∨ weak ∧ abs-failed(buf) ∧ lax = []
Proof step 7:
abs-failed(buf) ⊦ # buf = 0 ∧ lax = [] ∨ (∃ buf0, buf1. buf = buf0 + buf1 ∧ abs-padding(buf0) ∧ abs-nodes(buf1, n + # buf0, [], lax, weak)) ∨ weak ∧ abs-failed(buf) ∧ lax = [] ↔ lax = [] ∧ weak

Rule argument

spec: <toplevel> name: abs-nodes-base seq: ⊦ abs-nodes(buf, m, [], lax, weak) ↔ # buf = 0 ∧ lax = [] ∨ (∃ buf0, buf1. buf = buf0 + buf1 ∧ abs-padding(buf0) ∧ abs-nodes(buf1, m + # buf0, [], lax, weak)) ∨ weak ∧ abs-failed(buf) ∧ lax = [] subst: [weak, lax, m, buf] → [weak, lax, n, buf] flags: <all paths>

Additional information

Used terms: weak, lax, n, buf