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Proof step 2 from proof abs-nodes-add-crash-aligned-h (previous step)

abs-node(buf1, a), abs-nodes(buf0, m, x, lax, false), abs-nodes(subarray(buf0 + buf1, 0, n), m, x + a ', lax + @(m + # buf0, a.flashsize) ', boolvar), is-aligned(n, NODE_HEADER_SIZE), is-aligned(m, NODE_HEADER_SIZE), n ≤ # buf0 + # buf1 ⊦ n = # buf0 + # buf1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# buf1 = a.alignedsize + 2 * NODE_HEADER_SIZE, n < # buf0 + # buf1, abs-node(buf1, a), abs-nodes(subarray(buf0 + buf1, 0, n), m, x + a ', lax + @(m + # buf0, # buf1) ', boolvar), abs-nodes(buf0, m, x, lax, false), is-aligned(n, NODE_HEADER_SIZE), is-aligned(m, NODE_HEADER_SIZE) ⊦ n = # buf0 + # buf1

Rule argument

Additional information

Used simplifier rules: ls-abs-node-buf-size: ⊦ abs-node(buf, nd) → # buf = nd.alignedsize + 2 * NODE_HEADER_SIZE;%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ nd.flashsize = 2 * NODE_HEADER_SIZE + nd.alignedsize; (s)% ⊦ m ≠ n → (m ≤ n ↔ m < n); (s)