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Proof step 78 from proof abs-nodes-add-crash-aligned-h (previous step)

# buf1 = a.alignedsize + 2 * NODE_HEADER_SIZE, n < (# buf2 + # buf) + # buf1, abs-node(buf1, a), abs-nodes(subarray((buf2 + buf) + buf1, 0, n), m, (a0 ' + x0) + a ', lax + @(m + # buf2 + # buf, # buf1) ', boolvar), is-aligned(n, NODE_HEADER_SIZE), is-aligned(m, NODE_HEADER_SIZE), abs-padding(buf2) ∧ abs-nodes(buf, m + # buf2, a0 ' + x0, lax, false) ∨ lax ≠ [] ∧ lax.head.off = m ∧ lax.head.size = # buf2 ∧ abs-node(buf2, a0) ∧ abs-nodes(buf, lax.head.off + # buf2, x0, lax.tail, false), ∀ buf3, buf1, a, n, m, x, lax, boolvar. # buf3 < #(buf2 + buf) → # buf1 = a.alignedsize + 2 * NODE_HEADER_SIZE ∧ n < # buf3 + # buf1 ∧ abs-node(buf1, a) ∧ abs-nodes(subarray(buf3 + buf1, 0, n), m, x + a ', lax + @(m + # buf3, # buf1) ', boolvar) ∧ abs-nodes(buf3, m, x, lax, false) ∧ is-aligned(n, NODE_HEADER_SIZE) ∧ is-aligned(m, NODE_HEADER_SIZE) → n = # buf3 + # buf1 ⊦ n = (# buf2 + # buf) + # buf1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 79:
# buf1 = a.alignedsize + 2 * NODE_HEADER_SIZE, lax.head = @(m0, m1), n < (# buf2 + # buf) + # buf1, abs-node(buf1, a), abs-nodes(subarray((buf2 + buf) + buf1, 0, n), m, (a0 ' + x0) + a ', lax + @(m + # buf2 + # buf, # buf1) ', boolvar), is-aligned(m, NODE_HEADER_SIZE), is-aligned(n, NODE_HEADER_SIZE), abs-padding(buf2) ∧ abs-nodes(buf, m + # buf2, a0 ' + x0, lax, false) ∨ lax ≠ [] ∧ m0 = m ∧ m1 = # buf2 ∧ abs-node(buf2, a0) ∧ abs-nodes(buf, m0 + # buf2, x0, lax.tail, false), ∀ buf3, buf1, a, n, m, x, lax, boolvar. # buf3 < #(buf2 + buf) → # buf1 = a.alignedsize + 2 * NODE_HEADER_SIZE ∧ n < # buf3 + # buf1 ∧ abs-node(buf1, a) ∧ abs-nodes(subarray(buf3 + buf1, 0, n), m, x + a ', lax + @(m + # buf3, # buf1) ', boolvar) ∧ abs-nodes(buf3, m, x, lax, false) ∧ is-aligned(n, NODE_HEADER_SIZE) ∧ is-aligned(m, NODE_HEADER_SIZE) → n = # buf3 + # buf1 ⊦ n = (# buf2 + # buf) + # buf1

Rule argument

spec: laddress name: elim seq: ⊦ m = ladr.off ∧ m0 = ladr.size ↔ ladr = @(m, m0) subst: [ladr, m, m0] → [lax.head, m0, m1]

Additional information

Used simplifier rules: ⊦ m = ladr.off ∧ m0 = ladr.size ↔ ladr = @(m, m0); (elim) Used terms: lax.head, m0, m1