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Proof step 14 from proof abs-nodes-add-crash-aligned (previous step)

# buf1 = a.alignedsize + 2 * NODE_HEADER_SIZE, abs-node(buf1, a), abs-nodes(buf0, 0, x, lax, false), is-aligned(# buf0 + # buf1, EB_PAGE_SIZE), is-aligned(#(buf0 + buf1), EB_PAGE_SIZE) ⊦ abs-nodes(buf0 + buf1, 0, x + a ', lax + @(# buf0, # buf1) ', boolvar)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
# buf1 = a.alignedsize + 2 * NODE_HEADER_SIZE, abs-node(buf1, a), abs-nodes(buf0, 0, x, lax, false), is-aligned(# buf0 + # buf1, EB_PAGE_SIZE) ⊦ abs-nodes(buf1, # buf0, a ', @(# buf0, # buf1) ', boolvar)

Rule argument

Additional information

Used simplifier rules: abs-nodes-append-h: ⊦ abs-nodes(buf0, m, x0, lax0, false) → ( abs-nodes(buf0 + buf1, m, x0 + x1, lax0 + lax1, weak) ↔ abs-nodes(buf1, m + # buf0, x1, lax1, weak));%a: ⊦ (x + y) + z = x + y + z; from specification list%a: ⊦ (lax + lax0) + lax1 = lax + lax0 + lax1; from specification list[laddress-list]%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n + 0 = n; (s)%append-a: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1; from specification array-splice[buffer]% ⊦ #(buf + buf0) = # buf + # buf0; (s)