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Proof step 25 from proof abs-nodes-add-crash-aligned (previous step)

# buf = a.alignedsize, # buf2 = NODE_HEADER_SIZE, abs-nodes(buf0, 0, x, lax, false), is-aligned(2 * NODE_HEADER_SIZE + # buf0 + a.alignedsize, EB_PAGE_SIZE), is-encoded(nodeheader(node-size-headerless(a), false), buf2), is-encoded(a, subarray(buf, 0, node-size-headerless(a))) ⊦ ∃ buf4, buf3. buf2 + buf + validtrailer = buf4 + buf3 ∧ ( abs-padding(buf4) ∧ abs-nodes(buf3, # buf0 + # buf4, a ', @(# buf0, # buf4 + # buf3) ', boolvar) ∨ buf3 = mkbuf(0) ∧ abs-node(buf4, a))

User applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: buf2 + buf + validtrailer, mkbuf(0) abort: F discard: T computed: F

Additional information

Used simplifier rules: abs-nodes-mkbuf0-empty-h: ⊦ abs-nodes(mkbuf(0), m, x, lax, weak) ↔ x = [] ∧ lax = [];% ⊦ buf + mkbuf(0) = buf; (s)%append-a: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1; from specification array-splice[buffer]% ⊦ buf + buf0 = buf + buf1 ↔ buf0 = buf1; (s)% ⊦ #(buf + buf0) = # buf + # buf0; (s)% ⊦ # validtrailer = NODE_HEADER_SIZE; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ # mkbuf(n) = n; (s)% ⊦ n + 0 = n; (s)%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ a ' ≠ []; (s)%⊦ # buf1 = nd.alignedsize ∧ is-encoded(nodeheader(node-size-headerless(nd), false), buf0) ∧ is-encoded(nd, subarray(buf1, 0, node-size-headerless(nd))) → abs-node(buf0 + buf1 + validtrailer, nd); (ss) Used terms: buf2 + buf + validtrailer, mkbuf(0)