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Proof step 4 from proof abs-nodes-aligned-2headersize-h (previous step)

abs-nodes(buf, m, x, lax, false), ∀ buf0, m, x, lax. # buf0 < # buf → abs-nodes(buf0, m, x, lax, false) → is-aligned(# buf0, 2 * NODE_HEADER_SIZE) ⊦ is-aligned(# buf, 2 * NODE_HEADER_SIZE)

User applied rule constructor cut

And obtained the following new goals

Proof step 5:
x = [], abs-nodes(buf, m, x, lax, false), ∀ buf0, m, x, lax. # buf0 < # buf → abs-nodes(buf0, m, x, lax, false) → is-aligned(# buf0, 2 * NODE_HEADER_SIZE) ⊦ is-aligned(# buf, 2 * NODE_HEADER_SIZE)
Proof step 12:
x = nd + x0, abs-nodes(buf, m, x, lax, false), ∀ buf0, m, x, lax. # buf0 < # buf → abs-nodes(buf0, m, x, lax, false) → is-aligned(# buf0, 2 * NODE_HEADER_SIZE) ⊦ is-aligned(# buf, 2 * NODE_HEADER_SIZE)

Rule argument

var: x

Additional information

Used simplifier rules: list freely generated by [], +;;