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Proof step 21 from proof abs-nodes-aligned-headersize-h (previous step)

lax.head = @(m0, m1), abs-padding(buf1) ∧ abs-nodes(buf0, m + # buf1, nd ' + x0, lax, weak) ∨ lax ≠ [] ∧ m0 = m ∧ m1 = # buf1 ∧ abs-node(buf1, nd) ∧ abs-nodes(buf0, m + # buf1, x0, lax.tail, weak), ∀ buf2, m, x, lax, weak. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x, lax, weak) → is-aligned(# buf2, NODE_HEADER_SIZE) ⊦ is-aligned(# buf1 + # buf0, NODE_HEADER_SIZE)

User applied rule case distinction

And obtained the following new goals

Proof step 22:
lax.head = @(m0, m1), abs-nodes(buf0, m + # buf1, nd ' + x0, lax, weak), abs-padding(buf1), ∀ buf2, m, x, lax, weak. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x, lax, weak) → is-aligned(# buf2, NODE_HEADER_SIZE) ⊦ is-aligned(# buf1 + # buf0, NODE_HEADER_SIZE)
Proof step 27:
lax.head = @(m0, m1), m0 = m, m1 = # buf1, abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x0, lax.tail, weak), ∀ buf2, m, x, lax, weak. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x, lax, weak) → is-aligned(# buf2, NODE_HEADER_SIZE) ⊦ lax = [], is-aligned(# buf1 + # buf0, NODE_HEADER_SIZE)

Rule argument

pos: left 2

Proof step 21 from proof abs-nodes-aligned-headersize-h (previous step)

User applied rule case distinction

And obtained the following new goals

Rule argument

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