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Proof step 29 from proof abs-nodes-aligned-headersize-h (previous step)

# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, ladr = @(m, # buf1), lax = ladr + lax0, abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x0, lax0, weak), ∀ buf2, m, x, lax, weak. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x, lax, weak) → is-aligned(# buf2, NODE_HEADER_SIZE) ⊦ lax = [], is-aligned(# buf0, NODE_HEADER_SIZE)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x0, lax0, weak), ∀ buf2, m, x, lax, weak. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x, lax, weak) → is-aligned(# buf2, NODE_HEADER_SIZE) ⊦ is-aligned(# buf0, NODE_HEADER_SIZE)

Rule argument

Additional information

Used simplifier rules: a: ⊦ (lax + lax0) + lax1 = lax + lax0 + lax1; from specification list[laddress-list]% ⊦ ladr ' + lax ≠ []; (s)% ⊦ ladr + lax = ladr ' + lax; (s)