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Proof step 1 from proof abs-nodes-append-empty (conclusion)

⊦ abs-nodes(buf0, x0, lax0, false) → (abs-nodes(buf0 + buf1, x0, lax0, weak) ↔ abs-nodes(buf1, # buf0, [], [], weak))

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information