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Proof step 18 from proof abs-nodes-append-h (previous step)

lax0.head = @(m0, m1), abs-padding(buf2) ∧ abs-nodes(buf, m + # buf2, nd ' + x, lax0, false) ∨ lax0 ≠ [] ∧ m0 = m ∧ m1 = # buf2 ∧ abs-node(buf2, nd) ∧ abs-nodes(buf, m + # buf2, x, lax0.tail, false), ∀ buf3, m, x0, lax0, buf1, x1, lax1, weak. # buf3 < #(buf2 + buf) → abs-nodes(buf3, m, x0, lax0, false) → (abs-nodes(buf3 + buf1, m, x0 + x1, lax0 + lax1, weak) ↔ abs-nodes(buf1, m + # buf3, x1, lax1, weak)) ⊦ (∃ buf0, buf3. (buf2 + buf) + buf1 = buf0 + buf3 ∧ ( abs-padding(buf0) ∧ abs-nodes(buf3, m + # buf0, nd ' + x + x1, lax0 + lax1, weak) ∨ lax0 + lax1 ≠ [] ∧ (lax0 + lax1).head.off = m ∧ (lax0 + lax1).head.size = # buf0 ∧ abs-node(buf0, nd) ∧ abs-nodes(buf3, m + # buf0, x + x1, (lax0 + lax1).tail, weak))) ↔ abs-nodes(buf1, m + # buf2 + # buf, x1, lax1, weak)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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