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Proof step 30 from proof abs-nodes-append-h (previous step)

# buf2 = nd.alignedsize + 2 * NODE_HEADER_SIZE, lax0.head = @(m, # buf2), abs-node(buf2, nd), abs-nodes(buf, m + # buf2, x, lax0.tail, false), ∀ buf3, m, x0, lax0, buf1, x1, lax1, weak. # buf3 < #(buf2 + buf) → abs-nodes(buf3, m, x0, lax0, false) → (abs-nodes(buf3 + buf1, m, x0 + x1, lax0 + lax1, weak) ↔ abs-nodes(buf1, m + # buf3, x1, lax1, weak)) ⊦ (∃ buf0, buf3. (buf2 + buf) + buf1 = buf0 + buf3 ∧ ( abs-padding(buf0) ∧ abs-nodes(buf3, m + # buf0, nd ' + x + x1, lax0 + lax1, weak) ∨ lax0 + lax1 ≠ [] ∧ # buf2 = # buf0 ∧ abs-node(buf0, nd) ∧ abs-nodes(buf3, m + # buf0, x + x1, lax0.tail + lax1, weak))) ↔ abs-nodes(buf1, m + # buf2 + # buf, x1, lax1, weak), lax0 = []

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: list-data, inst: laddress-list name: elim-list-c seq: lax ≠ [] ⊦ ladr = lax.head ∧ lax0 = lax.tail ↔ lax = ladr + lax0 subst: [lax, ladr, lax0] → [lax0, ladr, lax]

Additional information

Used simplifier rules: lax ≠ [] ⊦ ladr = lax.head ∧ lax0 = lax.tail ↔ lax = ladr + lax0; (elim) Used terms: lax0, ladr, lax