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Proof step 16 from proof abs-nodes-at-least-flashsize (previous step)

# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, lax.head = @(m, # buf1), # buf0 < x0.flashsize, abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x0, lax.tail, false), ∀ buf2, x, m, lax. # buf2 < #(buf1 + buf0) → # buf2 < x.flashsize ∧ abs-nodes(buf2, m, x, lax, false) → x = [] ⊦ lax = [], x0 = []

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 17:
# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, ladr = @(m, # buf1), lax = ladr + lax0, # buf0 < x0.flashsize, abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x0, lax0, false), ∀ buf2, x, m, lax. # buf2 < #(buf1 + buf0) → # buf2 < x.flashsize ∧ abs-nodes(buf2, m, x, lax, false) → x = [] ⊦ lax = [], x0 = []

Rule argument

spec: list-data, inst: laddress-list name: elim-list-c seq: lax ≠ [] ⊦ ladr = lax.head ∧ lax0 = lax.tail ↔ lax = ladr + lax0 subst: [lax, ladr, lax0] → [lax, ladr, lax0]

Additional information

Used simplifier rules: lax ≠ [] ⊦ ladr = lax.head ∧ lax0 = lax.tail ↔ lax = ladr + lax0; (elim) Used terms: lax, ladr, lax0