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Proof step 2 from proof abs-nodes-at-least-flashsize (previous step)

abs-nodes(buf, m, x, lax, false) ⊦ # buf ≥ x.flashsize

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# buf < x.flashsize, abs-nodes(buf, m, x, lax, false) ⊦ x = []

Rule argument

Additional information

Used simplifier rules: flashsize-eq-0: ⊦ x.flashsize = 0 ↔ x = [];%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m ≤ n ↔ ¬ n < m; (ss)% ⊦ n ≥ m ↔ m ≤ n; (s)