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Proof step 14 from proof abs-nodes-before-no-address-h (previous step)

m0 < m, @(m0, m1) = @(m2, m3) ∨ @(m0, m1) ∈ lax0, abs-padding(buf1) ∧ abs-nodes(buf0, m + # buf1, nd ' + x0, @(m2, m3) ' + lax0, boolvar) ∨ m2 = m ∧ m3 = # buf1 ∧ abs-node(buf1, nd) ∧ abs-nodes(buf0, m + # buf1, x0, lax0, boolvar), ∀ buf2, m0, m, x, lax, boolvar, m1. # buf2 < #(buf1 + buf0) → m0 < m ∧ abs-nodes(buf2, m, x, lax, boolvar) ∧ @(m0, m1) ∈ lax → false ⊦

User applied rule case distinction

And obtained the following new goals

Proof step 15:
m0 < m, abs-nodes(buf0, m + # buf1, nd ' + x0, @(m2, m3) ' + lax0, boolvar), abs-padding(buf1), @(m0, m1) = @(m2, m3) ∨ @(m0, m1) ∈ lax0, ∀ buf2, m0, m, x, lax, boolvar, m1. # buf2 < #(buf1 + buf0) → m0 < m ∧ abs-nodes(buf2, m, x, lax, boolvar) ∧ @(m0, m1) ∈ lax → false ⊦
Proof step 20:
m2 = m, m3 = # buf1, m0 < m, abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x0, lax0, boolvar), @(m0, m1) = @(m2, m3) ∨ @(m0, m1) ∈ lax0, ∀ buf2, m0, m, x, lax, boolvar, m1. # buf2 < #(buf1 + buf0) → m0 < m ∧ abs-nodes(buf2, m, x, lax, boolvar) ∧ @(m0, m1) ∈ lax → false ⊦

Rule argument

pos: left 3

Proof step 14 from proof abs-nodes-before-no-address-h (previous step)

User applied rule case distinction

And obtained the following new goals

Rule argument

Additional information