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Proof step 17 from proof abs-nodes-beyond-no-address-h (previous step)

m2 = m, m3 = # buf1, abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x0, lax0, boolvar), (# buf1 + # buf0) + m ≤ m0, @(m0, m1) = @(m2, m3) ∨ @(m0, m1) ∈ lax0, ∀ buf2, m, x, lax, boolvar, m0, m1. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x, lax, boolvar) ∧ @(m0, m1) ∈ lax ∧ # buf2 + m ≤ m0 → false ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x0, lax0, boolvar), (# buf1 + # buf0) + m ≤ m0, @(m0, m1) = @(m, # buf1) ∨ @(m0, m1) ∈ lax0, ∀ buf2, m, x, lax, boolvar, m0, m1. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x, lax, boolvar) ∧ @(m0, m1) ∈ lax ∧ # buf2 + m ≤ m0 → false ⊦

Rule argument

Additional information

Used simplifier rules: ls-abs-node-buf-size: ⊦ abs-node(buf, nd) → # buf = nd.alignedsize + 2 * NODE_HEADER_SIZE;