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Proof step 3 from proof abs-nodes-beyond-no-address (previous step)

abs-nodes(buf, 0, x, lax, boolvar), @(m0, m1) ∈ lax, # buf ≤ m0 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ abs-nodes(buf, m, x, lax, boolvar) ∧ # buf + m ≤ m0 → ¬ @(m0, m1) ∈ lax

Rule argument

spec: <toplevel> name: abs-nodes-beyond-no-address-h seq: ⊦ abs-nodes(buf, m, x, lax, boolvar) ∧ # buf + m ≤ m0 → ¬ @(m0, m1) ∈ lax subst: [buf, m, x, boolvar, lax, m1, m0] → [buf, 0, x, boolvar, lax, m1, m0] flags: <all paths>

Additional information

Used simplifier rules: ⊦ n + 0 = n; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic Used terms: buf, 0, x, boolvar, lax, m1, m0