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Proof step 3 from proof abs-nodes-bothcrash-prefix (previous step)

abs-nodes((buf0 + buf1).align↓, 0, x1, lax1, boolvar1), abs-nodes(buf0.align↓, 0, x0, lax0, boolvar0) ⊦ x0 ⊑ x1 ∧ lax0 ⊑ lax1

User applied rule cut formula

And obtained the following new goals

Proof step 4:
abs-nodes(buf0.align↓, 0, x0, lax0, boolvar0), abs-nodes((buf0 + buf1).align↓, 0, x1, lax1, boolvar1), ∃ buf2, buf3. buf2 = buf0.align↓ ∧ buf2 + buf3 = (buf0 + buf1).align↓ ⊦ x0 ⊑ x1 ∧ lax0 ⊑ lax1
Proof step 7:
abs-nodes(buf0.align↓, 0, x0, lax0, boolvar0), abs-nodes((buf0 + buf1).align↓, 0, x1, lax1, boolvar1) ⊦ ∃ buf2, buf3. buf2 = buf0.align↓ ∧ buf2 + buf3 = (buf0 + buf1).align↓, x0 ⊑ x1 ∧ lax0 ⊑ lax1

Rule argument

fma: ∃ buf2, buf3. buf2 = buf0.align↓ ∧ buf2 + buf3 = (buf0 + buf1).align↓

Additional information

Used formulas: ∃ buf2, buf3. buf2 = buf0.align↓ ∧ buf2 + buf3 = (buf0 + buf1).align↓