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Proof step 14 from proof abs-nodes-case-distinction-h (previous step)

lax.head = @(m0, m1), abs-nodes(buf0, m + # buf1, nd ' + x0, lax, true), abs-padding(buf1) ⊦ ∃ buf3, buf2. buf1 + buf0 = buf3 + buf2 ∧ ( abs-padding(buf3) ∧ abs-nodes(buf2, m + # buf3, nd ' + x0, lax, true) ∨ lax ≠ [] ∧ (∃ lax0. lax = @(m, 2 * NODE_HEADER_SIZE + nd.alignedsize) ' + lax0) ∧ abs-node(buf3, nd) ∧ abs-nodes(buf2, m + # buf3, x0, lax.tail, true))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
abs-nodes(buf0, m + # buf1, nd ' + x0, @(m0, m1) ' + lax0, true), abs-padding(buf1) ⊦ ∃ buf, buf2. buf1 + buf0 = buf + buf2 ∧ ( buf1 = buf ∧ abs-nodes(buf2, m + # buf, nd ' + x0, @(m0, m1) ' + lax0, true) ∨ (∃ lax1. @(m0, m1) ' + lax0 = @(m, 2 * NODE_HEADER_SIZE + nd.alignedsize) ' + lax1) ∧ abs-node(buf, nd) ∧ abs-nodes(buf2, m + # buf, x0, lax0, true))

Rule argument

Additional information

Used simplifier rules: abs-nodes-first-adr-explicit: ⊦ abs-nodes(buf, m, a ' + x, lax, weak) → (lax.head = ladr ↔ (∃ lax0. lax = ladr + lax0));% ⊦ (ladr ' + lax).tail = lax; (s)% ⊦ ladr ' + lax ≠ []; (s)% ⊦ ladr ∈ ladr0 ' + lax ↔ ladr = ladr0 ∨ ladr ∈ lax; (s)%a: ⊦ (lax + lax0) + lax1 = lax + lax0 + lax1; from specification list[laddress-list]%in-14: ⊦ ladr ' + lax = lax0 → ladr ∈ lax0; (forward) from specification list[laddress-list]%⊦ buf0 + buf1 = buf2 + buf3 ∧ abs-padding(buf0) → (abs-padding(buf2) ↔ buf0 = buf2); (s)%append-a: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1; from specification array-splice[buffer]% ⊦ ladr + lax = ladr ' + lax; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list