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Proof step 35 from proof abs-nodes-crash-h (previous step)

abs-nodes(buf1, m + # buf0, [], [], true), abs-padding(buf0), is-aligned(n, NODE_HEADER_SIZE), # buf0 ≤ n, n ≤ # buf0 + # buf1, ∀ buf2, m, x, lax, n. # buf2 < #(buf0 + buf1) → abs-nodes(buf2, m, x, lax, true) ∧ is-aligned(n, NODE_HEADER_SIZE) ∧ n ≤ # buf2 → (∃ x0, lax0. x0 ⊑ x ∧ lax0 ⊑ lax ∧ abs-nodes(subarray(buf2, 0, n), m, x0, lax0, true)) ⊦ abs-nodes(subarray(buf1, 0, n - # buf0), m + # buf0, [], [], true)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 36:
n = n0 + # buf0, abs-nodes(buf1, m + # buf0, [], [], true), abs-padding(buf0), is-aligned(n, NODE_HEADER_SIZE), n ≤ # buf0 + # buf1, # buf0 ≤ n, ∀ buf2, m, x, lax, n. # buf2 < #(buf0 + buf1) → abs-nodes(buf2, m, x, lax, true) ∧ is-aligned(n, NODE_HEADER_SIZE) ∧ n ≤ # buf2 → (∃ x0, lax0. x0 ⊑ x ∧ lax0 ⊑ lax ∧ abs-nodes(subarray(buf2, 0, n), m, x0, lax0, true)) ⊦ abs-nodes(subarray(buf1, 0, n0), m + # buf0, [], [], true)

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [n, # buf0, n0]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n, # buf0, n0