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Proof step 10 from proof abs-nodes-elems-adr-length-h (previous step)

x = nd + x0, abs-nodes(buf, m, x, lax, weak), ∀ buf0, m, x, lax, weak. # buf0 < # buf → abs-nodes(buf0, m, x, lax, weak) → # x = # lax ⊦ # x = # lax

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
abs-nodes(buf, m, nd ' + x0, lax, weak), ∀ buf0, m, x, lax, weak. # buf0 < # buf → abs-nodes(buf0, m, x, lax, weak) → # x = # lax ⊦ # x0 + 1 = # lax

Rule argument

Additional information

Used simplifier rules: a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ m +1 = m + 1; (s)% ⊦ #(a ' + x) = (# x)+1; (s)% ⊦ a + x = a ' + x; (s)