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Proof step 15 from proof abs-nodes-elems-adr-length-h (previous step)

lax.head = @(m0, m1), abs-padding(buf1) ∧ abs-nodes(buf0, m + # buf1, nd ' + x0, lax, weak) ∨ lax ≠ [] ∧ m0 = m ∧ m1 = # buf1 ∧ abs-node(buf1, nd) ∧ abs-nodes(buf0, m0 + # buf1, x0, lax.tail, weak), ∀ buf2, m, x, lax, weak. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x, lax, weak) → # x = # lax ⊦ # x0 + 1 = # lax

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
lax.head = @(m0, m1), abs-padding(buf1) ∧ abs-nodes(buf0, m + # buf1, nd ' + x0, lax, weak) ∨ lax ≠ [] ∧ m0 = m ∧ m1 = # buf1 ∧ abs-node(buf1, nd) ∧ abs-nodes(buf0, m + # buf1, x0, lax.tail, weak), ∀ buf2, m, x, lax, weak. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x, lax, weak) → # x = # lax ⊦ # x0 + 1 = # lax

Proof step 15 from proof abs-nodes-elems-adr-length-h (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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