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Proof step 19 from proof abs-nodes-elems-adr-length-h (previous step)

lax.head = @(m0, m1), m0 = m, m1 = # buf1, abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x0, lax.tail, weak), ∀ buf2, m, x, lax, weak. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x, lax, weak) → # x = # lax ⊦ # x0 + 1 = # lax, lax = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, lax.head = @(m, # buf1), abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x0, lax.tail, weak), ∀ buf2, m, x, lax, weak. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x, lax, weak) → # x = # lax ⊦ # x0 + 1 = # lax, lax = []

Rule argument

Additional information

Used simplifier rules: ls-abs-node-buf-size: ⊦ abs-node(buf, nd) → # buf = nd.alignedsize + 2 * NODE_HEADER_SIZE;