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Proof step 3 from proof abs-nodes-elems-empty-adr-empty-h (previous step)

abs-nodes(buf, m, [], lax, weak) ⊦ lax = []

User applied rule apply lemma

And obtained the following new goals

Proof step 4:
⊦ abs-nodes(buf, m, x, lax, weak) → # x = # lax

Rule argument

spec: <toplevel> name: abs-nodes-elems-adr-length-h seq: ⊦ abs-nodes(buf, m, x, lax, weak) → # x = # lax subst: [buf, m, x, lax, weak] → [buf, m, [], lax, weak]

Additional information

Used simplifier rules: ⊦ # [] = 0; (s)% ⊦ # lax = 0 ↔ lax = []; (s) Used terms: buf, m, [], lax, weak