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Proof step 14 from proof abs-nodes-emptyheader-h (previous step)

x = nd + x0, isempty(buf, 0, NODE_HEADER_SIZE) ⊦ abs-nodes(buf, m, x, lax, weak) ↔ (buf = mkbuf(0) ∨ abs-failed(buf) ∧ weak) ∧ x = [] ∧ lax = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
abs-nodes(buf, m, nd ' + x0, lax, weak), isempty(buf, 0, NODE_HEADER_SIZE) ⊦

Rule argument

Additional information

Used simplifier rules: a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ a ' + x ≠ []; (s)% ⊦ a + x = a ' + x; (s)