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Proof step 23 from proof abs-nodes-emptyheader-h (previous step)

# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, ladr = @(m, # buf1), lax = ladr + lax0, abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x0, lax0, weak), isempty(buf1 + buf0, 0, NODE_HEADER_SIZE) ⊦ lax = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, abs-node(buf1, nd), abs-nodes(buf0, m + # buf1, x0, lax0, weak), isempty(buf1 + buf0, 0, NODE_HEADER_SIZE) ⊦

Rule argument

Additional information

Used simplifier rules: a: ⊦ (lax + lax0) + lax1 = lax + lax0 + lax1; from specification list[laddress-list]% ⊦ ladr ' + lax ≠ []; (s)% ⊦ ladr + lax = ladr ' + lax; (s)