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Proof step 4 from proof abs-nodes-emptyheader-h (previous step)

x = [], isempty(buf, 0, NODE_HEADER_SIZE) ⊦ abs-nodes(buf, m, x, lax, weak) ↔ (buf = mkbuf(0) ∨ abs-failed(buf) ∧ weak) ∧ x = [] ∧ lax = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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