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Proof step 11 from proof abs-nodes-first-adr-explicit (previous step)

lax.head = @(m0, m1), m0 = m, m1 = # buf1, abs-node(buf1, a), abs-nodes(buf0, m + # buf1, x, lax.tail, weak), ∀ buf2, m, a, x, lax, weak. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, a ' + x, lax, weak) → (∃ lax0. lax = lax.head ' + lax0) ⊦ lax = [], ∃ lax0. lax = @(m0, m1) ' + lax0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
# buf1 = a.alignedsize + 2 * NODE_HEADER_SIZE, lax.head = @(m, # buf1), abs-node(buf1, a), abs-nodes(buf0, m + # buf1, x, lax.tail, weak), ∀ buf2, m, a, x, lax, weak. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, a ' + x, lax, weak) → (∃ lax0. lax = lax.head ' + lax0) ⊦ lax = [], ∃ lax0. lax = @(m, # buf1) ' + lax0

Rule argument

Additional information

Used simplifier rules: ls-abs-node-buf-size: ⊦ abs-node(buf, nd) → # buf = nd.alignedsize + 2 * NODE_HEADER_SIZE;