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Proof step 2 from proof abs-nodes-first-adr-explicit (previous step)

abs-nodes(buf, m, a ' + x, lax, weak) ⊦ lax.head = ladr ↔ (∃ lax0. lax = ladr + lax0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
abs-nodes(buf, m, a ' + x, lax, weak) ⊦ ∃ lax0. lax = lax.head ' + lax0

Rule argument

Additional information

Used simplifier rules: a: ⊦ (lax + lax0) + lax1 = lax + lax0 + lax1; from specification list[laddress-list]% ⊦ (ladr ' + lax).head = ladr; (s)% ⊦ ladr + lax = ladr ' + lax; (s)