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Proof step 2 from proof abs-nodes-no-padding-last (previous step)

# buf = (x + a ').flashsize ⊦ abs-nodes(buf, m, x + a ', lax + ladr ', false) ↔ (∃ buf0, buf1. buf = buf0 + buf1 ∧ abs-nodes(buf0, m, x, lax, false) ∧ abs-node(buf1, a) ∧ ladr = @(# buf0 + m, a.flashsize))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# buf = (x + a ').flashsize ⊦ abs-nodes(buf, m, x + a ', lax + ladr ', false) ↔ (∃ buf0, buf1. buf = buf0 + buf1 ∧ abs-nodes(buf0, m, x, lax, false) ∧ abs-node(buf1, a) ∧ ladr = @(# buf0 + m, 2 * NODE_HEADER_SIZE + a.alignedsize))

Rule argument

Additional information

Used simplifier rules: ⊦ nd.flashsize = 2 * NODE_HEADER_SIZE + nd.alignedsize; (s)