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Proof step 4 from proof abs-nodes-no-padding-one (previous step)

# buf = (a + []).flashsize ⊦ abs-nodes(buf, m, a + [], lax, false) ↔ lax = @(m, # buf) ' ∧ abs-node(buf, a)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ a + x = a ' + x
Proof step 6:
# buf = (a ' + []).flashsize ⊦ abs-nodes(buf, m, a ' + [], lax, false) ↔ lax = @(m, # buf) ' ∧ abs-node(buf, a)

Rule argument

spec: list name: c seq: ⊦ a + x = a ' + x subst: [x, a] → [[], a] flags: <all paths>

Additional information

Used terms: [], a