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Proof step 9 from proof abs-nodes-no-padding-one (previous step)

# buf0 = a.alignedsize + 2 * NODE_HEADER_SIZE, lax.head.size = # buf0, lax.tail = [], abs-node(buf0, a) ⊦ lax = [], lax = @(lax.head.off, # buf0) '

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 10:
# buf0 = a.alignedsize + 2 * NODE_HEADER_SIZE, ladr.size = # buf0, lax = ladr + lax0, lax0 = [], abs-node(buf0, a) ⊦ lax = @(ladr.off, # buf0) ', lax = []

Rule argument

spec: list-data, inst: laddress-list name: elim-list-c seq: lax ≠ [] ⊦ ladr = lax.head ∧ lax0 = lax.tail ↔ lax = ladr + lax0 subst: [lax, ladr, lax0] → [lax, ladr, lax0]

Additional information

Used simplifier rules: lax ≠ [] ⊦ ladr = lax.head ∧ lax0 = lax.tail ↔ lax = ladr + lax0; (elim) Used terms: lax, ladr, lax0