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Proof step 14 from proof abs-nodes-nodups-h (previous step)

@(m0, m1) ∈ lax0 ∨ dups(lax0), abs-padding(buf1) ∧ abs-nodes(buf0, m + # buf1, nd ' + x0, @(m0, m1) ' + lax0, boolvar) ∨ m0 = m ∧ m1 = # buf1 ∧ abs-node(buf1, nd) ∧ abs-nodes(buf0, m + # buf1, x0, lax0, boolvar), ∀ buf2, m, x, lax, boolvar. # buf2 < #(buf1 + buf0) → abs-nodes(buf2, m, x, lax, boolvar) ∧ dups(lax) → false ⊦

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 2

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