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Proof step 23 from proof abs-nodes-nospace-header-h (previous step)

# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, lax.head = @(n, # buf1), # buf1 + # buf0 < 2 * NODE_HEADER_SIZE + align↑(m, 2 * NODE_HEADER_SIZE), abs-node(buf1, nd), abs-nodes(buf0, n + # buf1, x0, lax.tail, weak), is-encoded(nodeheader(m, boolvar0), subarray(buf1, 0, NODE_HEADER_SIZE)), NODE_HEADER_SIZE ≤ # buf1 + # buf0 ⊦ lax = []

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 24:
# buf1 = nd.alignedsize + 2 * NODE_HEADER_SIZE, ladr = @(n, # buf1), lax = ladr + lax0, # buf1 + # buf0 < 2 * NODE_HEADER_SIZE + align↑(m, 2 * NODE_HEADER_SIZE), abs-node(buf1, nd), abs-nodes(buf0, n + # buf1, x0, lax0, weak), is-encoded(nodeheader(m, boolvar0), subarray(buf1, 0, NODE_HEADER_SIZE)), NODE_HEADER_SIZE ≤ # buf1 + # buf0 ⊦ lax = []

Rule argument

spec: list-data, inst: laddress-list name: elim-list-c seq: lax ≠ [] ⊦ ladr = lax.head ∧ lax0 = lax.tail ↔ lax = ladr + lax0 subst: [lax, ladr, lax0] → [lax, ladr, lax0]

Additional information

Used simplifier rules: lax ≠ [] ⊦ ladr = lax.head ∧ lax0 = lax.tail ↔ lax = ladr + lax0; (elim) Used terms: lax, ladr, lax0